H
hairo
Guest
guys,
siapa pun bisa menjelaskan kepada saya fungsi dalam count_motor sinyal kode ini.itu setara dengan negara (negara mesin)?kode ini saya dapatkan dari sebuah buku.i perlu memahami kode ini karena itu adalah bagian dari proyek desain.LIBRARY IEEE;
USE IEEE.STD_LOGIC_1164.ALL;
USE IEEE.STD_LOGIC_ARITH.ALL;
USE IEEE.STD_LOGIC_UNSIGNED.ALL;
ENTITY MOTOR_CONTROL IS
PORT (clk_1khz: IN STD_LOGIC;
lmotor_dir, rmotor_dir: IN STD_LOGIC;
lmotor_speed, rmotor_speed: IN STD_LOGIC;
lmotor, rmotor: OUT STD_LOGIC):
END MOTOR_CONTROL;
ARSITEKTUR PERILAKU MOTOR_CONTROL IS
SIGNAL count_motor: STD_LOGIC_VECTOR (4 downto 0);
BEGIN
PROSES
BEGIN
MENUNGGU SAMPAI clk_1khz EVENT DAN clk_1khz = 1;
JIKA count_motor / = 19 THEN
count_motor <= count_motor 1;
ELSE
Count_motor = 00.000;
END IF;
JIKA count_motor = 17 THEN
- don t menghasilkan setiap denyut
JIKA lmotor_speed = 0 THEN
lmotor <= 0;
ELSE
lmotor <= 1;
END IF;
JIKA rmotor_speed = 0 THEN
rmotor <= 0;
ELSE
rmotor <= 1;
END IF;
Elseif count_motor = 18 THEN
JIKA lmotor_speed = 1 THEN
CASE IS lmotor_dir
- FORWARD
KETIKA 0 =>
lmotor <= 1;
- reverse
KETIKA 1 =>
lmotor <= 0;
WHEN OTHERS => NULL;
END CASE;
ELSE
Lmotor <= 0;
END IF;
JIKA rmotor_speed = 1 THEN
CASE IS rmotor_dir
- FORWARD
KETIKA 0 =>
rmotor <= 0;
- reverse
KETIKA 1 =>
rmotor <= 1;
WHEN OTHERS => NULL;
END CASE;
ELSE
Lmotor <= 0;
END IF;
ELSE
Lmotor <= 0;
Rmotor <= 0;
END IF;
END PROCESS;
END PERILAKU;thanks in advance.
salam,
hairo
siapa pun bisa menjelaskan kepada saya fungsi dalam count_motor sinyal kode ini.itu setara dengan negara (negara mesin)?kode ini saya dapatkan dari sebuah buku.i perlu memahami kode ini karena itu adalah bagian dari proyek desain.LIBRARY IEEE;
USE IEEE.STD_LOGIC_1164.ALL;
USE IEEE.STD_LOGIC_ARITH.ALL;
USE IEEE.STD_LOGIC_UNSIGNED.ALL;
ENTITY MOTOR_CONTROL IS
PORT (clk_1khz: IN STD_LOGIC;
lmotor_dir, rmotor_dir: IN STD_LOGIC;
lmotor_speed, rmotor_speed: IN STD_LOGIC;
lmotor, rmotor: OUT STD_LOGIC):
END MOTOR_CONTROL;
ARSITEKTUR PERILAKU MOTOR_CONTROL IS
SIGNAL count_motor: STD_LOGIC_VECTOR (4 downto 0);
BEGIN
PROSES
BEGIN
MENUNGGU SAMPAI clk_1khz EVENT DAN clk_1khz = 1;
JIKA count_motor / = 19 THEN
count_motor <= count_motor 1;
ELSE
Count_motor = 00.000;
END IF;
JIKA count_motor = 17 THEN
- don t menghasilkan setiap denyut
JIKA lmotor_speed = 0 THEN
lmotor <= 0;
ELSE
lmotor <= 1;
END IF;
JIKA rmotor_speed = 0 THEN
rmotor <= 0;
ELSE
rmotor <= 1;
END IF;
Elseif count_motor = 18 THEN
JIKA lmotor_speed = 1 THEN
CASE IS lmotor_dir
- FORWARD
KETIKA 0 =>
lmotor <= 1;
- reverse
KETIKA 1 =>
lmotor <= 0;
WHEN OTHERS => NULL;
END CASE;
ELSE
Lmotor <= 0;
END IF;
JIKA rmotor_speed = 1 THEN
CASE IS rmotor_dir
- FORWARD
KETIKA 0 =>
rmotor <= 0;
- reverse
KETIKA 1 =>
rmotor <= 1;
WHEN OTHERS => NULL;
END CASE;
ELSE
Lmotor <= 0;
END IF;
ELSE
Lmotor <= 0;
Rmotor <= 0;
END IF;
END PROCESS;
END PERILAKU;thanks in advance.
salam,
hairo